From: Brett Creeley <brett.creeley@intel.com>
Date: Thu, 25 Jul 2019 01:55:29 -0700
Subject: ice: Assume that more than one Rx queue is rare in ice_napi_poll
Patch-mainline: v5.4-rc1
Git-commit: 9118fcd5255f6d3891c90e01edd98dfc402ac663
References: jsc#SLE-7926
Currently we divide budget by the number of Rx queues per Rx ring
container in ice_napi_poll even if there is only 1. This is an
unnecessary divide for the normal case of 1 Rx ring per Rx ring
container. Fix this by using an unlikely() call in the case where we
actually need to divide.
Also, we will always set budget_per_ring even if there are no Rx rings
in the Rx ring container so we don't need to initialize it to 0.
Signed-off-by: Brett Creeley <brett.creeley@intel.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
Acked-by: Thomas Bogendoerfer <tbogendoerfer@suse.de>
---
drivers/net/ethernet/intel/ice/ice_txrx.c | 15 ++++++++++-----
1 file changed, 10 insertions(+), 5 deletions(-)
--- a/drivers/net/ethernet/intel/ice/ice_txrx.c
+++ b/drivers/net/ethernet/intel/ice/ice_txrx.c
@@ -1414,8 +1414,8 @@ int ice_napi_poll(struct napi_struct *na
container_of(napi, struct ice_q_vector, napi);
struct ice_vsi *vsi = q_vector->vsi;
bool clean_complete = true;
- int budget_per_ring = 0;
struct ice_ring *ring;
+ int budget_per_ring;
int work_done = 0;
/* Since the actual Tx work is minimal, we can give the Tx a larger
@@ -1429,11 +1429,16 @@ int ice_napi_poll(struct napi_struct *na
if (budget <= 0)
return budget;
- /* We attempt to distribute budget to each Rx queue fairly, but don't
- * allow the budget to go below 1 because that would exit polling early.
- */
- if (q_vector->num_ring_rx)
+ /* normally we have 1 Rx ring per q_vector */
+ if (unlikely(q_vector->num_ring_rx > 1))
+ /* We attempt to distribute budget to each Rx queue fairly, but
+ * don't allow the budget to go below 1 because that would exit
+ * polling early.
+ */
budget_per_ring = max(budget / q_vector->num_ring_rx, 1);
+ else
+ /* Max of 1 Rx ring in this q_vector so give it the budget */
+ budget_per_ring = budget;
ice_for_each_ring(ring, q_vector->rx) {
int cleaned;